Measure the universe
From Kepler to Newton
Kepler III
where $a$ is the semi-major axis
Acceleration of circular motion
f=rv2 By assuming circular orbits of planets, we have
f=v2r−1∝P2r∝r3r=r−2 which is consistent with Newton II
F=r2Gm1m2 Various astrophysical objects
Using the tool
rv2=r2GM⇒M=Gv2r we can measure
The sun
For the first time we are able to measure the solar mass
P=2πGM⊙a3⇒M⊙=GP24π2a3=G×(1 yr)24π2×(1.5×108 km)3=2×1033 g Star cluster
R∼1 pc, σ∼20 km/s⇒M∼105M⊙, ρ∼105 M⊙/pc−3 Dynamic mass $\sim$ Visible mass
Galaxy
R∼10 kpc, σ∼200 km/s⇒M∼1011M⊙, ρ∼10−1 M⊙/pc−3 Discovery of dark matter - Dynamic mass $>$ Visible mass
SMBH (Sgr A*)
R∼0.01 pc, σ∼500 km/s⇒M∼2×106M⊙, ρ∼2×1012 M⊙/pc−3 In such high mass density, the average distance between two stars (solar mass) is
D∼21/31×10−4 pc∼20 AU Cosmology
Typical acceleration
Estimation using hubble timescale and speed of light
a∼rv2∼10 Gyr⋅cc2∼10−7cm/s/yr Two-body problem
Assuming two point mass $m_1$ and $m_2$ rotating around the common CoM
m1r¨1=∣r2−r1∣3Gm1m2(r2−r1)m2r¨2=−∣r2−r1∣3Gm1m2(r2−r1) Let $\vec r=\vec r_2-\vec r_1$, we have
m1r¨1=r3Gm1m2r,m2r¨2=−r3Gm1m2r Trajectory
In an effective one-body problem, we consider only the evolution of $\vec r$
r¨=−r3G(m1+m2)r≡−r3Gmr Test mass moves around $m_1+m_2$
Energy
E=21m1r˙12+21m2r˙22−rGm1m2=21[m1(m1+m2m2)2+m2(m1+m2m1)2]r˙2−rGm1m2=21m1+m2m1m2r˙2−rGm1m2=m1+m2m1m2[21r˙2−rG(m1+m2)] where
μ=m1+m2m1m2 is the reduced mass, and
21r˙2−rG(m1+m2) is known as the specific energy in the effective one-body system
Angular momentum
J=m1r1×r˙1+m2r2×r˙2=[m1(m1+m2m2)2+m2(m1+m2m1)2]r×r˙=μr×r˙ where
r×r˙ is the specific angular momentum