Chapter 2 Newtonian Cosmology
Last updated
Last updated
Recession velocity if B as seen by A is
Hubble expansion is a natural property of an expanding universe that obeys the cosmological principle
coordinates that are carried along with the expansion
comoving with space distance $\vec r$, comoving distance $\vec x$ (constant)
$a(t)$ is the scale factor - all we want to find out
Birkhoof's theorem: the net gravitational effect of a uniform external medium on a spherical cavity is zero, the net gravitational effect comes from matter internal to radius $r$ (as a mass point)
total energy of a particle of mass $m$ at A, B, C, D
$k$ must be independent of $x$, therefore $U\propto x^2$
$k$ is a independent of $t$, for $U$ is conserved
Thus $k$ is just a constant
$k>0\Rightarrow UT$ , collapse
$k<0\Rightarrow U<0, V<T$ , expand forever
$k=0\Rightarrow U=0$ , expansion terminates when $t\to\infty$
Hubble parameter
which is a function of time, so called Hubble constant $H_0$ is the Hubble parameter at present
Using Hubble parameter we can rewrite Friedmann equation
if $k=0$ , the critical density $\rho$ is then
In thermodynamics, the first law points that
where $P$ is the pressure, $S$ is the entropy
Expanding volume $V$ of unit comoving radius $x=1 (r=a)$, $E=mc^2$, energy within the volume
Assuming a reservable expansion $\text dS=0$ , we obtain the fluid equation
The first term - the dilution in the density because the volume has increased
The second term - the loss in energy because the pressure of the material has done work as the universe’s volume increased.
Equation of state
There is a unique pressure associated with each density,
For non-relativistic matter, $P=0$ , dust
For highly-relativistic matter , $P=\rho c^2/3$ , radiation pressure of light
Time-derivation on both sides of the Friedmann equation
Acceleration equation
Analytical solution
$k=0$
Dust, $P=0$
However, the current age of universe $t_0$ obtained in this model is wrong
Radiation, $P=\rho c^2/3$
Radiation dominated universe
Unstable, the radiation density decreases faster than the dust density, the universe will turn to matter dominated on day
Matter dominated universe
Stable
In a shell from $r$ to $r+\mathrm d r$, the total number of stars is $4\pi r^2n_0\mathrm d r$, where $n_0$ is the number density
Total intensity of the sky
which is $10^{13}$ times brighter than it actually is
Thermodynamic problem
Infinite volume
Infinite time to reach thermodynamic equilibrium
BUT the universe is not homogeneous (not the temperature of CMB)